Series LC Circuit: Caps & Resonators - Tapping Resonant Frequency

  • Thread starter Idea04
  • Start date
In summary, a resonant circuit will have a LOW impedance at resonance, leading to a voltage sag. A capacitor and coil will resonate at some frequency, but the actual voltage step-up depends on the reactances of the components.
  • #1
Idea04
194
1
For a series LC circuit, can a bipolar electrolytic capacitor be used. Also how do you tap the resonant frequency from a series LC circuit.
 
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  • #2
If you have a coil and a capacitor in series and put an AC signal across the series pair, the voltage across each of them will rise a lot at resonance, especially if the coil has low resistance.
So, you can choose if you take the output across the capacitor or the coil. It will be a much magnified version of the input.

You probably could use bipolar electrolytics, but the circuit you used them in might not have a very good resonance.
This is because large capacitors (which these capacitors are ) need a very large current through them to develop big voltages.
So, unless you can deliver such currents, you are better off calculating your resonance so that the components have a reactance of at least 200 ohms.

For example, a capacitor of 0.796 uF and a coil of 31.8 mH would resonate at about 1000 Hz and could give quite a good resonance.
You could resonate at 1000 Hz with 15.9 uF and 1.59 mH but the resonance would be very poor if you only had a signal generator to put the AC across the circuit.
In the first case, the components have a reactance of 200 ohms. In the second, 10 ohms.

The 15.9 uF capacitor could be a bipolar electrolytic but it would also have to have low ESR which is Equivalent Series Resistance.

If you are thinking of trying this, the output resistance of the signal generator appears in series with the tuned circuit, so you would normally put a small resistor across the signal generator. Maybe 10 ohms or so.

.
 
Last edited:
  • #3
vk6kro said:
If you have a coil and a capacitor in series and put an AC signal across the series pair, the voltage across both of them will rise a lot at resonance, especially if the coil has low resistance.

A series resonant circuit will have a LOW impedance at resonance causing the voltage to sag.
 
  • #4
For a low current application would a ceramic capacitor work better.
 
  • #5
Tell me if I'm wrong with this , But I thought that if you had a supply current of 1 amp then a 1 Farad cap would work. And if you had a supply current of 3.3 micro amps a 3.3 micro Farad cap would work.
 
  • #6
The voltage across each of the components will rise dramatically at resonance.
This rise in output is very useful if you have a low impedance source driving a high impedance load as you can get a substantial voltage gain.


Tell me if I'm wrong with this , But I thought that if you had a supply current of 1 amp then a 1 Farad cap would work. And if you had a supply current of 3.3 micro amps a 3.3 micro Farad cap would work.


No, that isn't true.
It has more to do with the reactance of the components. Any capacitor and coil will resonate at some frequency, but the actual voltage step-up depends on the reactances of the components. The voltage is equal to the reactance times the current and reactance depends on frequency. Even at 1 Hz a 1 Farad capacitor only has a reactance of 0.16 ohms so 1 amp through it would produce a voltage of 0.16 volts

For a low current application would a ceramic capacitor work better.
Better than an electrolytic? Yes, much better.
Ceramic capacitors work well in resonant circuits. They change capacitance with temperature but low temperature coefficient ones are available.
 

1. What is a Series LC Circuit?

A Series LC Circuit is an electrical circuit that consists of inductors (L) and capacitors (C) connected in series. This type of circuit is used to create a resonant frequency, where the impedance of the circuit is at its minimum.

2. How does a Series LC Circuit work?

In a Series LC Circuit, the inductor and capacitor work together to create a resonant frequency. The inductor stores energy in its magnetic field, while the capacitor stores energy in its electric field. When the two components are in series, the energy is constantly transferred back and forth between them, creating the resonant frequency.

3. What is resonant frequency in a Series LC Circuit?

Resonant frequency is the frequency at which the inductive reactance (XL) and capacitive reactance (XC) in a Series LC Circuit are equal. This means that the impedance of the circuit is at its minimum, resulting in a higher current flow through the circuit.

4. How do you calculate the resonant frequency of a Series LC Circuit?

The resonant frequency of a Series LC Circuit can be calculated using the formula f = 1/(2π√(LC)), where f is the resonant frequency in Hertz (Hz), L is the inductance in Henrys (H), and C is the capacitance in Farads (F).

5. What is the purpose of tapping into the resonant frequency in a Series LC Circuit?

Tapping into the resonant frequency in a Series LC Circuit allows for the efficient transfer of energy between the inductor and capacitor. This can be useful in applications such as radio communication, where the resonant frequency is used to tune the circuit to a specific frequency for optimal signal transmission and reception.

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