A red car is sitting at a stop light at rest. When the light turns green two things happen simultaneously; (1) the red car accelerates to a speed of 34.3 m/s in 8.92 seconds and then maintains that 34.3 m/s speed and (2) a blue car passes by the red car at a constant speed of 21.5 m/s.
Red Car: Vo=0 Vf=34.3 m/s a=3.84 (34.3/8.92)
Blue Car: Vo=21.5 m/s Vf=21.5 m/s
How much time (in seconds) will have elapsed from when the light turned green until the two cars are side-by-side?
distance = 1/2(Vo + Vf)t
distance = Vot + 1/2at^2
The Attempt at a Solution
I thought I would make them equal to each other, 1/2(Vo +Vf)t=Vot +1/2at^2 And find out what t equals to find out the time however It has yet to work after many attempts. Vo Any help is appreciated.
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