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A car is turning on a banked curve. The coefficient static friction between the car and the pavement is 0.30 and the coefficient of kinetic friction is 0.25.

The angle of the banking is 25 degrees, and the radius of the curve is 50 m. What is the minimum speed the car can have before sliding down the banking. I have found the maximum speed the car can have without sliding up the banking.

For the sliding up the bank I did this:

b=angle

s= coefficient of static friction

Fx = n*sin (b) + sin (b)*n*s = ma

Fy = n*cos (b) - mg - cos(b)*n*s = 0

So this is when the car is in equlibrium.

From this I find the acceleration and then the speed

I haven't figured out a relation between the speed and movement down the banking. I tried to resolve the weight vector into components together with the friction but I didn't get anywhere with that. The weight has some part in this I know. I'm just really lost. Could someone please give me a hint to this problem. The coefficient of kinetic friction is given but I don't see I have to use it.

With thanks,

Swatch

The angle of the banking is 25 degrees, and the radius of the curve is 50 m. What is the minimum speed the car can have before sliding down the banking. I have found the maximum speed the car can have without sliding up the banking.

For the sliding up the bank I did this:

b=angle

s= coefficient of static friction

Fx = n*sin (b) + sin (b)*n*s = ma

Fy = n*cos (b) - mg - cos(b)*n*s = 0

So this is when the car is in equlibrium.

From this I find the acceleration and then the speed

I haven't figured out a relation between the speed and movement down the banking. I tried to resolve the weight vector into components together with the friction but I didn't get anywhere with that. The weight has some part in this I know. I'm just really lost. Could someone please give me a hint to this problem. The coefficient of kinetic friction is given but I don't see I have to use it.

With thanks,

Swatch

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