Car speed and distance problem

  • Thread starter aricho
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In summary, Bart Simpson and his mother noticed that the McDonalds signs along the Pacific Highway were evenly spaced. Bart calculated that the distance between each sign was 166.67 meters, using the fact that the number of signs multiplied by 10 is equal to the car's speed in km/hr. This can also be written algebraically as x= 10/60 = 1/6 km, where x is the distance between signs. When asked about the intervals between the signs, it was explained that there are n-1 intervals between n signs.
  • #1
aricho
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Bart simpson drove at a steady speed along the pacific highway with his mother beside him

"have you noticed," he said "that the McDonalds signs seem to be evenly spaced along the side of the road? i wonder how far apart they are"

Mrs Simpson glanced at her watch, then counted the number of mcdonalds signs they passed in one minute.

What a strange coincidence" exclaimed bart, "when you multiply the number by 10 it is exactly equal to the speed of our car in km/h (kilometers per hour)

Assuming that the car is traveling at a constant speed and the minute began and ended midway between the 2 signs, how far is it between one sign and the next?

I have the answer, it's 166.67 meters, found by:

Suppose they pass 6 signs, so the speed is 60km/h
therefore 1km/minute
1km/6signs=0.16(repepater) km

try with 8, 10,200, all equals the same in the end.

So, my question is, how do i write this algebraically, what is the formal method?
 
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  • #2
Let x be the distance between two signs, in km. If you pass n signs, the you have traveled nx km (there are n-1 intervals between the signs and you start and end the minute half way between signs which adds another x interval). Therefore, if you pass n signs in one minute, your speed is nx km per minute or 60nx km/hr. We are told that the number of signs times 10 is equal to the speed in km/hr: 10n= 60nx. Very conveniently, the n's cancel and x= 10/60 = 1/6 km just as you got. Frankly, I prefer your method!
 
  • #3
HallsofIvy said:
Let x be the distance between two signs, in km. If you pass n signs, the you have traveled nx km (there are n-1 intervals between the signs and you start and end the minute half way between signs which adds another x interval). Therefore, if you pass n signs in one minute, your speed is nx km per minute or 60nx km/hr. We are told that the number of signs times 10 is equal to the speed in km/hr: 10n= 60nx. Very conveniently, the n's cancel and x= 10/60 = 1/6 km just as you got. Frankly, I prefer your method!

Sorry to bother you, but why are there n-1 intervals between each sign?
 
  • #4
If there is 1 sign, there are no intervals.
If there are 2 signs, there is one interval bwteween the first sign and second sign.
If there are 3 signs, there are 2 intervals, the first interval between the first and second signs, the second inetrval between the second and third sign.

So if there are n signs, there are n-1 intervals between the signs.
 

1. How is car speed and distance related?

Car speed and distance are directly related. As the speed of the car increases, the distance it travels in a given time also increases. This can be calculated using the formula distance = speed x time.

2. How does acceleration affect car speed and distance?

Acceleration is the rate at which the car's speed changes over time. When a car accelerates, its speed increases and therefore the distance it travels in a given time also increases. This can be calculated using the formula distance = 0.5 x acceleration x (time)^2.

3. How do factors such as air resistance and road conditions affect car speed and distance?

Air resistance and road conditions can have an impact on a car's speed and distance. Air resistance can slow down a car's speed, while road conditions such as friction can affect the distance the car travels. These factors can be taken into account in calculations, but can also vary depending on the specific conditions.

4. How can car speed and distance be measured accurately?

Car speed and distance can be measured using various tools and methods such as radar guns, GPS systems, and speedometers. These measurements can also be verified through mathematical calculations using the appropriate formulas.

5. How can car speed and distance be used in real-life scenarios?

Car speed and distance calculations are useful in many real-life scenarios, such as determining the time it will take to reach a destination, calculating fuel efficiency, and understanding the impact of speed on braking distance. These calculations can also help in making informed decisions while driving, such as maintaining a safe distance from other vehicles.

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