Car traveling up a slope

1. The problem statement, all variables and given/known data

A car traveling at 31.48 m/s runs out of gas while traveling up a 35° slope. How far up the hill will it coast before starting to roll back down?

2. Relevant equations

Ax=acos(35) Ay=asin(35)
deltaV/2a=distance


3. The attempt at a solution

I made the final velocity 0 seeing as it has to come to a complete stop before rolling back and i found the Ax and Ay which was 8.028 and 5.621. I thought if i then plugged in the corresponding accelerations (Ax and Ay) into delta x(or y)= Vf^2-Vi^2/2*Ax(or Ay) that would give me the distance in the x and y direction and from there i could use the equation delta x^2+delta y^2= c^2. and from there I would get the distance traveled up. Apparently thats wrong. What else should I try.

 

The Ay is the acceleration component parellel to the slope so I use that instead of 9.8. I miss read the equation I thought that Ax^2+Ay^2=A^2 gave you the acceleration on the slope but in reality it was just giving me the acceleration because of gravity. I got the right anwser what I did was just took the Ay and plugged it into the the equation Vf^2-Vi^2/2*Ay*distance of slope. I got it now. Thanks!

PS
If anyone has trouble with the problem I will show you my work for the problem via email or pm.