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Car turning

  1. Oct 11, 2007 #1
    1. The problem statement, all variables and given/known data
    When you take your 1100-kg car out for a spin, you go around a corner of radius 55m with a speed of 15m/s. Assuming your car doesn't skid, what is the force exerted on it by static friciton?


    2. Relevant equations
    f[tex]_{}c[/tex]=ma[tex]_{}c[/tex]
    f[tex]_{}c[/tex]=mv[tex]^{}2[/tex]/r
    [tex]\sumf=ma[/tex]

    3. The attempt at a solution
    [tex]\sum[/tex]f=ma
    f[tex]_{}s[/tex]=mv[tex]^{}2[/tex]/r
    f[tex]_{}s[/tex]=300

    300=[tex]\mu[/tex][tex]_{}s[/tex]mg
    300=[tex]\mu[/tex][tex]_{}s[/tex](1100)(908)
    [tex]\mu_{}s[/tex]=0.027

    but apparantley it's supposed to be 4.5
    what happened?
     
  2. jcsd
  3. Oct 11, 2007 #2

    learningphysics

    User Avatar
    Homework Helper

    How did you get 300?

    And why are you calculating the coefficient of friction? The question only asks for the force.
     
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