# Carbon-14 Decay

#### stephaniek

The radiocarbon in our bodies is one of the naturally occurring sources of radiation. Let's see how large a dose we receive. 14C decays via B- emission, and 18.0% of our body's mass is carbon.

a) Write out the decay scheme of carbon-14 and show the end product. (A neutrino is also produced.)
answer: 146C ------> e- + 147N + ve

b) Neglecting the effects of the neutrino, how much kinetic energy (in MeV ) is released per decay? The atomic mass of C-14 is 14.003242 u.
No idea where to begin tried using E = mc2 did not get the right answer.

c) How many grams of carbon are there in a 76.0 kg person?
no idea how to do this.

d) How many decays per second does this carbon produce? (Hint: Assume activity of C-14 is about 0.255 Bq per gram of carbon.)

Any help would be greatly appreciated.

#### hamster143

How many grams of carbon are there in a 76.0 kg person?
no idea how to do this.
Carbon is 18.0% of body mass. 76.0 times 18.0%.

How many decays per second does this carbon produce? (Hint: Assume activity of C-14 is about 0.255 Bq per gram of carbon.)
Look up the definition of Bq (Becquerel) in Wikipedia.

#### arivero

Gold Member
It seems that it is a problem allowing you to use tables. Obviously to use E=mc2 (how do you pretend use it, anyway?) you need the mass difference between carbon and nitrogen. The data of the atomic mass of C-14 is in part a need and in part a red herring (so naive people will try to apply E=mc2 to it, instead asking the tables for the atomic mass of N-14 too).

The radiocarbon in our bodies is one of the naturally occurring sources of radiation. Let's see how large a dose we receive. 14C decays via B- emission, and 18.0% of our body's mass is carbon.

a) Write out the decay scheme of carbon-14 and show the end product. (A neutrino is also produced.)
answer: 146C ------> e- + 147N + ve

b) Neglecting the effects of the neutrino, how much kinetic energy (in MeV ) is released per decay? The atomic mass of C-14 is 14.003242 u.
No idea where to begin tried using E = mc2 did not get the right answer.

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