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Carnot Cycle Efficiency

  1. Jul 1, 2012 #1
    1. The problem statement, all variables and given/known data

    A Carnot engine operates between 230°C and 120°C, absorbing 6.30*10^4 J per cycle at the higher temperature.

    What is the efficiency of the engine?

    2. Relevant equations

    eff = 1 - (Tcold/Thot)

    3. The attempt at a solution

    Using this equation, I get 47.83 percent, which the system is telling me is incorrect. Can anybody offer a solution to this? Thanks.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jul 1, 2012 #2
    i was not using kelvin, so i got the answer
     
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