The exhaust temperature of a Carnot heat engine is 401◦ C.
What is the intake temperature if the eﬃciency of the engine is 40.2 %?
Answer in units of ◦ C.
e = 1 - Tc/Th (all in Kelvin)
The Attempt at a Solution
0.402 = 1 - Tc/ (401+273) = 1 - Tc/674
Tc = 0.598 * 674 = 403.052
Tc in C = 403.052-273 = 130.052
But somehow this answer seems to be wrong on the quest. This is my last problem ..please help? What am I doing wrong? Am I missing something?