- #1

physicsss

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The Q that is required to freeze the cube is (37/1000)kg*(4186J/K)(20K)+(37/1000)kg(3.33 x 10^5)

The coefficient of performance of ice is equal to TL/(TH - TL)=QL/(QH-QL), so pluging it the stuff, I get (200+273)/((500+273)-(200+273))= QL/ (300-QL), so I solved for QL and divide the Q needed to melt ice by QL. But my answer is wrong. Why? The 300W is QH, right?