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Carnot heat engine

  • Thread starter Carlo09
  • Start date
  • #1
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Homework Statement


A heat pump takes heat from a hot resevoir and disipates heat to a cold one. Both resevoirs are equal mass and specific heat capacity. Show that as the heat engine does maximal work the final temp of the resevoirs = Tf = SQRT(TcTh)


Homework Equations


Qin = Wout + Qout
mc(Th-Tf) = Wout + mc(Tf -Tc)

Efficiency = Wout/Win = 1- (Qin/Qout)


The Attempt at a Solution


Well I know i somehow need to get TcTh^2 in order to get the solution so I used efficiecy as 1 for maximal work out but I also assumed no work in which means I'm dividing by 0! Or if I say 1= 1-Qin/Qout then Qout = 1-Qin and now im just confused. Help please :)
 

Answers and Replies

  • #2
hotvette
Homework Helper
994
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Remember from calculus how to find the maximum (or minimim) of a function?
 
  • #3
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Remember from calculus how to find the maximum (or minimim) of a function?
Are you meaning differentiate and set to 0 and then solve? Differentiate again and is D^2f(x)/Dx^2 < 0 then it's a maximum?
 
  • #4
hotvette
Homework Helper
994
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Are you meaning differentiate and set to 0 and then solve?
Yep, but you should only have to differentiate once. It should be pretty clear whether you have a max or min.
 
  • #5
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Yep, but you should only have to differentiate once. It should be pretty clear whether you have a max or min.
Thank you, Which equation do I differentiate?
 
  • #6
15
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Thank you, Which equation do I differentiate?
Ooo right ok so I have dw/dQ_h = (T1-T2)/T1 = 0

therefore T1-T2 = 0 so T1=T2=T and so

dw/dQ_h = (T-T)/T which is 0 which doesnt help me :S
 

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