A lawnmower engine with an efficiency of 0.22 rejects 9900 J of heat every second. What is the magnitude of the work that the engine does in one second? e = 0.22 Qc = 9900 J/s e = W/Qh Qh = Qc + W e = W / Qc + W 0.22 = W / 9900 + W 0.22(9900 + W) = W 2178 + 0.22W = W W = 2792.31 J/s? I checked my answer on cramster.com but they have something different, but I believe my answer to be right. Can anybody verify if I am doing this correctly or not? Thank you.