Please check my answers.(adsbygoogle = window.adsbygoogle || []).push({});

A 1200-kg station wagon is moving along a straight highway at 12.0 m/s. Another car, with mass 1800 kg and speed 20.0 m/s, has its center of mass 40.0 m ahead of the center of mass of the station wagon.

a)Find the position of the center of mass of the system consisting of the two automobiles.

b) Find the magnitude of the total momentum of the system from the above data.

c) Find the speed of the center of mass of the system.

d) Find the total momentum of the system, using the speed of the center of mass.

a.x_cm = [40 m(1200 kg)]/(1200 kg + 1800 kg) = 16 m ? I set the car with the greater mass at (0,0).

b.Total p = 1200 kg*12 m/s + 1800 kg*20.0 m/s = 50400 kg*m/s

c.V_cm = (50400 kg*m/s)/( 1800 kg + 1200 kg) = 16.8 m/s

d.Using the answer from part c, (16.8 m/s)*(1200 kg + 1800 kg) = 50400 kg*m/s again

Thanks.

**Physics Forums - The Fusion of Science and Community**

# Cars and Center of Mass

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Cars and Center of Mass

Loading...

**Physics Forums - The Fusion of Science and Community**