1. The problem statement, all variables and given/known data A thief steals a car in front of two cops, A and B. The thief's initial velocity is 25m/s, cop A starts his car with 3m/s2, and cop B starts 10 seconds after cop A, but with 5m/s2. After 200m from his initial point, the thief notices the cops and start accelerating at 1m/s2 Which cop catches the thief? At what time does he catch it? 2. Relevant equations d= Vot+1/2at2 I think that's the only required formula 3. The attempt at a solution I tried to set an equality between the distance of the thief and the distance of cop A, but I get stuck in the math to solve for t. (25m/s)(t)+(1/2)(m/s2)+200m=(1.5m/s2)(t+8)2 t is the time since the thief started accelerating, and that happens 8s after A started. after doing math here I get completely stuck with the algebra.