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Cart friction problem

  1. Dec 1, 2009 #1
    a horizontal force of 200 Newtons is applied to a 55 kg cart across a 10 meter surface. If the cart accelerates at 2 meters/second squared, then what is the work done by the force of friction as it acts to retard the motion of the cart ??

    Work= FX
    work= maX

    55 kg x 2 x 10 = 1100 - 200 N = 900 Joules ??

    is this correct ?
  2. jcsd
  3. Dec 2, 2009 #2


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    Re: friction

    It is not correct. The "F" in F = ma is the net force, i.e. the sum of all the forces. In this case, it is the vector sum of the 200 N and the force of friction. What expression do you know that gives you the force of (kinetic) friction? Use that to calculate the work done by it.
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