1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Cart friction problem

  1. Dec 1, 2009 #1
    a horizontal force of 200 Newtons is applied to a 55 kg cart across a 10 meter surface. If the cart accelerates at 2 meters/second squared, then what is the work done by the force of friction as it acts to retard the motion of the cart ??

    Work= FX
    work= maX

    55 kg x 2 x 10 = 1100 - 200 N = 900 Joules ??


    is this correct ?
     
  2. jcsd
  3. Dec 2, 2009 #2

    kuruman

    User Avatar
    Homework Helper
    Gold Member

    Re: friction

    It is not correct. The "F" in F = ma is the net force, i.e. the sum of all the forces. In this case, it is the vector sum of the 200 N and the force of friction. What expression do you know that gives you the force of (kinetic) friction? Use that to calculate the work done by it.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Cart friction problem
  1. Box on Cart (Friction) (Replies: 5)

  2. Cart with Friction (Replies: 5)

  3. Cart with Friction (Replies: 3)

  4. Cart Problem (Replies: 5)

Loading...