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## Homework Statement

A cat walks along a uniform plank that is 4.20 long and has a mass of 5.00 . The plank is supported by two sawhorses, one 0.440 from the left end of the board and the other 1.50 from its right end.

If the cat has a mass of 3.3 , how close to the right end of the two-by-four can it walk before the board begins to tip?

## Homework Equations

Net force = 0

Net torque = 0

F=ma

Torque = r * F * sin(theta)

## The Attempt at a Solution

Since the board is just beginning to tip, there is no weight on the left sawhorse.

So the right side the torque is equal to the force (mass * g) times the distance which is the unkown?

Force = 3.3*9.81 = 32.37 N

Torque = 32.37 N * d?

I'm stuck....