A cat walks along a uniform plank that is 4.20 long and has a mass of 5.00 . The plank is supported by two sawhorses, one 0.440 from the left end of the board and the other 1.50 from its right end.
If the cat has a mass of 3.3 , how close to the right end of the two-by-four can it walk before the board begins to tip?
Net force = 0
Net torque = 0
Torque = r * F * sin(theta)
The Attempt at a Solution
Since the board is just beginning to tip, there is no weight on the left sawhorse.
So the right side the torque is equal to the force (mass * g) times the distance which is the unkown?
Force = 3.3*9.81 = 32.37 N
Torque = 32.37 N * d?