# Catapult Problem

## Homework Statement

Catapults date from thousands of years ago, and were used historically to launch everything from stones to horses. During a battle in what is now Bavaria, inventive artillerymen from the united German clans launched giant spaetzle from their catapults toward a Roman fortification whose walls were 8.50 m high. The catapults launched spaetzle projectiles from a height of 3.30 m above the ground, and a distance of 39.1 m from the walls of the fortification at an angle of 60.0 degrees above the horizontal (see figure). The projectiles were to hit the top of the wall, splattering the Roman soldier atop the wall with pulverized pasta. (For the following questions, ignore any effects due to air resistance.)

What launch speed was necessary?

How long were the spaetzle in the air?

At what speed did the projectiles hit the wall?

## Homework Equations

Velocity in M/S
Time in seconds
x = x(initial) + velocity*t(s)+.5*a(t^2)
Vf^2 = VI^2 + 2*a*x (x = distance)

## The Attempt at a Solution

The problem is submitted via webassign and i've tried solving the right triangle made by the distance and the difference in heights of the starting location and ending location. (39.44 m) and then attempting to treat the projection with that being the total x-change and solving another right triangle to change the acceleration.

I'm rather lost I know the physics of the problem (x-velocity independent of acceleration) and y-component dependent upon the velocity up. Any tips how to start this problem would be greatly appreciated.

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Delphi51
Homework Helper
difference in heights of the starting location and ending location. (39.44 m) and then attempting to treat the projection with that being the total x-change
Surely the difference in heights is 5.2 m: launched from 3.3 m and walls are 8.5m.

You must keep horizontal numbers separate from vertical ones all the way through. No triangles.

Surely the difference in heights is 5.2 m: launched from 3.3 m and walls are 8.5m.

You must keep horizontal numbers separate from vertical ones all the way through. No triangles.
Thanks, but I was able to solve the first two questions and I am working on the last one.

I created two formulas for the summations of the x and y vectors(both of which had the total summation of the launch vector) and solved in terms of time (in air). I set equal to each other and solved.