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Homework Help: Catenary Curve

  1. Jan 12, 2006 #1
    I am curious as to how the equation of a catenary was derived:

    x = t
    y = a*cosh(t)

    Does anyone have any insight on this or know a good webpage that can explain it?

    Thank you for the assistance.
     
  2. jcsd
  3. Jan 13, 2006 #2
    Here's the most in depth I could find:

    http://www.kmlhs.org/faculty/TKUEHL/Precalculus/MESA/Arch/Arch%20History.htm [Broken]
     
    Last edited by a moderator: May 2, 2017
  4. Jan 13, 2006 #3
    Its long and complicated. I would get a nice statics book to show you the solution.


    http://planetmath.org/encyclopedia/ChainCurve.html [Broken]

    (Link really does not show you how anything is derived though)

    http://www.whim.org/nebula/math/catenary.html [Broken]

    (again not great)

    Go get yourself Statics by RC Hibbeler, and Ill help you if u are stuck.
     
    Last edited by a moderator: May 2, 2017
  5. Jan 13, 2006 #4
    Thanks for the links. I actually found something almost identical to the material on the Planetmath site (it also had a picture, though). For now, I think something like that is sufficient (although I'm sure I'll come across it in a future class). Thanks again...
     
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