in a CRT, the deflection on the screen is 2.4 cm when the accelerating voltage is 480 V and the deflecting voltage is 36 V. what deflection on the screen will you see if the accelerating voltage is 960 V (doubled) and the deflecting voltage is 18 V (halfed)?(adsbygoogle = window.adsbygoogle || []).push({});

answer is 0.6 cm

can anyone please explain how to do this qeustion. (i tried, but there are so many formulas to plug and it's very complicated, one have to keep track of every change in the speed, then time, then distance, then finally the deflection. i am sure theres a better way to do it, like using a ratio, but i have no idea how to do it....)

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# Homework Help: Cathode ray tube(CRT) question

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