- #1
- 19
- 0
Hi,
I'm stuck on this question:
Use the Cauchy's integral to show [tex]\oint[/tex]cos(z) / [ z (z2 +9) ] dz = 2[tex]\pi[/tex]i/9
C is within the square defined by x= +/- 2 , y = +/- 2
I can't see how to get the denominator in the form (z-z0) to apply the theorem. Any help would be much appreciated!
[
I'm stuck on this question:
Use the Cauchy's integral to show [tex]\oint[/tex]cos(z) / [ z (z2 +9) ] dz = 2[tex]\pi[/tex]i/9
C is within the square defined by x= +/- 2 , y = +/- 2
I can't see how to get the denominator in the form (z-z0) to apply the theorem. Any help would be much appreciated!
[