[tex]y'=\sin (x+y+3)[/tex](adsbygoogle = window.adsbygoogle || []).push({});

[tex] y(0)=-3 [/tex]

I tried substituting [tex] x+y+3=u [/tex] and solving I get

[tex] \tan (u(x)) - \sec (u(x)) = x [/tex]

but what the heck can I do now?

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# Cauchy prob.

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