If i have a closed pathintegral of the form:(adsbygoogle = window.adsbygoogle || []).push({});

(sin(z)+3cos(z) + 3e^z)/((z-(pi/2)^2)

How is cauchys integral formula applicable? If I split the integral into partial fractions wont i still get A/(z-pi/2) + B/(z-pi/2)^2, the B part of which wont be applicable to cauchys formula since the denominator is still squared.

In short, how do i apply cauchys formula to integrals with a denominator with a power higher than 1.

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# Cauchys integral formula.

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