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Celsius to Kelvin conversion problem (Kinetic theory)
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[QUOTE="Forco, post: 5384551, member: 585526"] [h2]Homework Statement [/h2] Find the temperature T that allows the rms speed of a gas to be equal to another gas with T=47°C. The molecular mass of the first gas is 64, and the molecular mass of the second gas is 32. [h2]Homework Equations[/h2] [tex]v_{rms}= \sqrt{\frac{3RT}{M}}[/tex] [h2]The Attempt at a Solution[/h2] The problem is actually very easy. It's actually really simple to conclude that [tex]T_1=2T_2[/tex]. However, my problem arises when actually replacing the given temperature. If I take the second temperature to equal 47°C, then the first temperature is equal to 94°C. And converting that to kelvin gives 367.15 K. However, if instead I use directly the temperature in K (47+273.15), then my answer becomes 640.3 K. Which one is right? I assume the second one because in order for the equation to make sense, T needs to be expressed in K. I'd like to be sure, however. [/QUOTE]
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Celsius to Kelvin conversion problem (Kinetic theory)
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