# Center of gravity of a car

1. Nov 20, 2005

Find the center of gravity of a car with respect to the front axle. There is a distance of 130 inches between the front and back axles. There is a force of 1800lbs on the back axle and 2100lbs on the front axle.

I changed 130 inches to meters and I got 3.30m. I changed both 1800lbs and 2100lbs to Newtons and I got 8010N and 9345N respectively. I divided each by 9.8 to get their masses.

I then divided 3.30m by the sum of 817.3g + 953.6g. I got .0019m. So that means that the center of gravity is .0019m away from the front axle or .075inches.

Did I do this correctly? My answer does not seem to make much conceptual sense...

2. Nov 20, 2005

### Staff: Mentor

No, you didn't do this correctly. The center of mass is defined as:
$$(m_1 x_1 + m_2 x_2 + ...)/M_{total}$$

But you can also think of the center of mass as that point about which the net torque due the object's weight would be zero. (No need to do any unit conversions.) You have one torque pulling clockwise, the other counterclockwise: set them equal to each other.

3. Nov 20, 2005

That makes sense.

I set the CG x inches away from the front axle, which means that it has to be 130-x inches away from the back axle.

1800(130-x)=2100x
234000=3900x
x=60

So the CG must be 60" away from the front axle, which makes sense.

Thanks