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Center of gravity of a stick

  1. Nov 1, 2007 #1
    1. The problem statement, all variables and given/known data

    Three uniform meter sticks, each of mass m, are placed on the floor as follows: stick 1 lies along the y axis from y = 0.500 m to y = 1.50 m, stick 2 lies along the x axis from x = 0.110 m to x = 1.11 m, stick 3 lies along the x axis from x = 1.34 m to x = 2.34 m. Calculate the location of the center of mass of the meter sticks. Enter the x value first and then the y value.

    2. Relevant equations

    m1*y1+m2*y2.../m1+m2...

    3. The attempt at a solution

    this is the problem that i have to figure out. i know the equation for the center of gravity as being basically (m1y1+m2y2...)/m1+m2+... but since these are meter sticks and they all have the same weight yet take up more than one point on the system, i dont know where to go from here...can someone please help me?
     
  2. jcsd
  3. Nov 1, 2007 #2

    Dick

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    They are uniform sticks, so the center of mass is at the center of the stick.
     
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