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**If you put a uniform block at the edge of a table, the center of the block must be over the table for the block not to fall off.**

If you stack two identical blocks at the table edge, the center of the top block must be over the bottom block, and the center of gravity of the two blocks together must be over the table. In terms of the length L of each block, what is the maximum overhang possible?

If you stack two identical blocks at the table edge, the center of the top block must be over the bottom block, and the center of gravity of the two blocks together must be over the table. In terms of the length L of each block, what is the maximum overhang possible?

Repeat for 3 and 4 books.

This problem is really confusing to me. For one book, the maximum overhang is .5L.

Say that weight of the book = w.

If I take the torques from the right edge of the furthest book,

[tex]\sum \tau = 0 = -w * .5L + F_n * .5L[/tex]

For two books...

[tex] \sum \tau = 0 = 2w * (answer L) = w * (?L) + w*(?L)[/tex]

I don't know how to get the coefficients in the question marks... Actually, is that even the right equation?

Thanks for your help!

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