Please help this is due by Monday at 8:00am Eastern time. I don't know if I am did this problem correctly, please help.(adsbygoogle = window.adsbygoogle || []).push({});

Here is the question:

A bicycle is resting against a small step whose height is h=0.120m. The weight and radius of the wheel are W= 25.0 N, and r=0.340m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins to rise up and loses contact with the ground. What is the magnitude of the force when this happens?

This is what I did:

torque=-F*(0.120m)+W(0.340m)=0

=-F(0.120m)+(25.0 N)*(0.340)=0

F=(25.0 N)*(0.340m)/(0.120m)=70.83= F=71 N

Please tell me if this is correct or not before Monday, I am a new member to this site so please bear with me--Thanks!

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# Center of gravity-torque

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