A door of width 1.10 m and height 1.93 m weighs 290 N and is supported by two hinges, one a distance 0.500 m from the top and the other a distance 0.500 m from the bottom. Each hinge supports half the total weight of the door.(adsbygoogle = window.adsbygoogle || []).push({});

Assuming that the door's center of gravity is at its center, find the horizontal components of force exerted on the door by each hinge.

** Let H1 and H2 = forces exerted by the upper and lower hinges therefore:

H1_vert = H2_vert = weight/2 = 290 N / 2 = 145 N and the horizontal components of the hinge forces are equal in magnitude and opposite in direction.

net torque = 0 give H1_hor(1.10 m) - w(0.50 m) = 0 solve for H1_hor

H1_hor = 290N(0.50m/1.10m) - 145 N

I don't think this equation is correct.

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# Homework Help: Center of gravity

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