A door of width 1.10 m and height 1.93 m weighs 290 N and is supported by two hinges, one a distance 0.500 m from the top and the other a distance 0.500 m from the bottom. Each hinge supports half the total weight of the door. Assuming that the door's center of gravity is at its center, find the horizontal components of force exerted on the door by each hinge. ** Let H1 and H2 = forces exerted by the upper and lower hinges therefore: H1_vert = H2_vert = weight/2 = 290 N / 2 = 145 N and the horizontal components of the hinge forces are equal in magnitude and opposite in direction. net torque = 0 give H1_hor(1.10 m) - w(0.50 m) = 0 solve for H1_hor H1_hor = 290N(0.50m/1.10m) - 145 N I don't think this equation is correct.