- 3

- 0

At t= 1 sec , F = .5 x10^3

At t= 2 sec , F = 1 x10^3

At t= 3 sec , F = 1.5 x10^3

At t= 4 sec , F = 2 x10^3

At t= 5 sec , F = 2x10^3

At t= 6 sec , F = 2 x10^3

At t= 7 sec , F = 1.5 x10^3

At t= 8 sec , F = 1 x10^3

At t= 9 sec , F = .5 x10^3

At t= 10 sec , F = 0 x10^3

a) Use the time and force to find the total impulse given to the ball

b) Determine the horizontal velocity of the ball immediately after the collision (you can’t assume the collision is elastic)

c) Determine the following for the cube immediately after the collision:

i. Its speed

ii. Its direction of travel (right or left) , if moving

d.) determine the distance between the two points of impact of the objects with the floor

for part a.) i did impulse = momentum = F*t, but i dont think thats right

for part b.) the equation i used was Vif= (m1-m2)/(m1+m2) but this wasn't correct either

for part c.) i used the equation v2f= (2m1)/(m1+m2), which again was wrong

for part d.)to find the distance i used the equation y = v1t + 1/2gt^2 for both distances which again was wrong