- #1
zen123
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A 4.5 kg ball initially rest at the edge of a 2.5 m long, 1.5 m high frictionless table. A hard plastic cube of mass 0.65 kg slides across the table at a speed of 20m/s and strikes the ball to leave the table in the direction in which the cube was moving.
At t= 1 sec , F = .5 x10^3
At t= 2 sec , F = 1 x10^3
At t= 3 sec , F = 1.5 x10^3
At t= 4 sec , F = 2 x10^3
At t= 5 sec , F = 2x10^3
At t= 6 sec , F = 2 x10^3
At t= 7 sec , F = 1.5 x10^3
At t= 8 sec , F = 1 x10^3
At t= 9 sec , F = .5 x10^3
At t= 10 sec , F = 0 x10^3
a) Use the time and force to find the total impulse given to the ball
b) Determine the horizontal velocity of the ball immediately after the collision (you can’t assume the collision is elastic)
c) Determine the following for the cube immediately after the collision:
i. Its speed
ii. Its direction of travel (right or left) , if moving
d.) determine the distance between the two points of impact of the objects with the floor
for part a.) i did impulse = momentum = F*t, but i don't think that's right
for part b.) the equation i used was Vif= (m1-m2)/(m1+m2) but this wasn't correct either
for part c.) i used the equation v2f= (2m1)/(m1+m2), which again was wrong
for part d.)to find the distance i used the equation y = v1t + 1/2gt^2 for both distances which again was wrong
At t= 1 sec , F = .5 x10^3
At t= 2 sec , F = 1 x10^3
At t= 3 sec , F = 1.5 x10^3
At t= 4 sec , F = 2 x10^3
At t= 5 sec , F = 2x10^3
At t= 6 sec , F = 2 x10^3
At t= 7 sec , F = 1.5 x10^3
At t= 8 sec , F = 1 x10^3
At t= 9 sec , F = .5 x10^3
At t= 10 sec , F = 0 x10^3
a) Use the time and force to find the total impulse given to the ball
b) Determine the horizontal velocity of the ball immediately after the collision (you can’t assume the collision is elastic)
c) Determine the following for the cube immediately after the collision:
i. Its speed
ii. Its direction of travel (right or left) , if moving
d.) determine the distance between the two points of impact of the objects with the floor
for part a.) i did impulse = momentum = F*t, but i don't think that's right
for part b.) the equation i used was Vif= (m1-m2)/(m1+m2) but this wasn't correct either
for part c.) i used the equation v2f= (2m1)/(m1+m2), which again was wrong
for part d.)to find the distance i used the equation y = v1t + 1/2gt^2 for both distances which again was wrong