1. The problem statement, all variables and given/known data A man is standing 1 meter in from the left of a 4 meter long beam. The beam is held up by two wires perpendicular to the beam. The beam is 750 N and the man is 100kg what are the tensions of the two wires. 2. Relevant equations F = ma Torque = F x d 3. The attempt at a solution I know that because the beam is not accelerating the sum of the forces is 0 so Fy = -750 - 980 + T1 + T2 = 0 T1+T2 = 1730 T2 = 1730 - T1 Torque (I put my pivot point at the first tension wire making it 0) Torue = F x d = T2 * 4Sin(90) - 1730 T2 *4 = 1730 T2 = 423.5 1730 - 423.5 = 1306.5 = T1 Now the book says 1130 T1 and 610 T2 I know for sure i'm missing something with center of mass im just not sure what.