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y3ahright
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Homework Statement
A man is standing 1 meter in from the left of a 4 meter long beam. The beam is held up by two wires perpendicular to the beam. The beam is 750 N and the man is 100kg what are the tensions of the two wires.
Homework Equations
F = ma
Torque = F x d
The Attempt at a Solution
I know that because the beam is not accelerating the sum of the forces is 0
so Fy = -750 - 980 + T1 + T2 = 0
T1+T2 = 1730
T2 = 1730 - T1
Torque (I put my pivot point at the first tension wire making it 0)
Torue = F x d = T2 * 4Sin(90) - 1730
T2 *4 = 1730
T2 = 423.5
1730 - 423.5 = 1306.5 = T1
Now the book says 1130 T1 and 610 T2
I know for sure I'm missing something with center of mass I am just not sure what.