(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A man is standing 1 meter in from the left of a 4 meter long beam. The beam is held up by two wires perpendicular to the beam. The beam is 750 N and the man is 100kg what are the tensions of the two wires.

2. Relevant equations

F = ma

Torque = F x d

3. The attempt at a solution

I know that because the beam is not accelerating the sum of the forces is 0

so Fy = -750 - 980 + T1 + T2 = 0

T1+T2 = 1730

T2 = 1730 - T1

Torque (I put my pivot point at the first tension wire making it 0)

Torue = F x d = T2 * 4Sin(90) - 1730

T2 *4 = 1730

T2 = 423.5

1730 - 423.5 = 1306.5 = T1

Now the book says 1130 T1 and 610 T2

I know for sure i'm missing something with center of mass im just not sure what.

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# Homework Help: Center of mass and Tension

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