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Introductory Physics Homework Help
Calculating Center of Mass in NH3 Molecule
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[QUOTE="JessicaHelena, post: 6061350, member: 643879"] [h2]Homework Statement [/h2] In the ammonia (NH3) molecule of the figure, the three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance [I]d[/I] = 9.40 ✕ 10^−11 m from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen-to-hydrogen distance is [I]L[/I] = 10.14 ✕ 10^−11 m. (a) What is the [I]x[/I] coordinate of the molecule's center of mass? (b) What is the [I]y[/I] coordinate of the molecule's center of mass? [h2]Homework Equations[/h2] x_cm = sum of (m*x)/M (same for y) [h2]The Attempt at a Solution[/h2] (a) I'm not quite sure how to deal with the two hydrogens towards the negative x-axis — they're not exactly on the axis at all. (b) None of the H's have any y values, so I did 13.9*sqrt(L^2-d^2)/(13.9+3*1) where 3*1 accounted for the masses of the three H's, but apparently that answer is wrong, and I've no idea why it is. (I got 1.137*10^-(10).) [/QUOTE]
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Calculating Center of Mass in NH3 Molecule
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