# Center of mass, moment of inertia for x = y^2 and y = x - 2 with density d = 3x

1. Apr 13, 2005

### VinnyCee

Here is the problem:

A region is defined as being bounded by the parabola $$x = y^2$$ and the line $$y = x - 2$$.

The density of this region is $$\delta = 3x$$.

a) Find the center of mass.

b) Find the moment of inertia about the y-axis.

Here is what I have:

$$M = \int_{-1}^{2}\int_{y^2}^{y + 2}\;3x\;dx\;dy = \frac{108}{5}$$

$$M_{x} = \int_{-1}^{2}\int_{y^2}^{y + 2} 3xy\;dx\;dy = \frac{135}{8}$$

$$M_{y} = \int_{-1}^{2}\int_{y^2}^{y + 2} 3x^2\;dx\;dy = \frac{1269}{28}$$

$$\bar{x} = \frac{\frac{1269}{28}}{\frac{108}{5}} = \frac{235}{112}\;\;and\;\;\bar{y} = \frac{\frac{135}{8}}{\frac{108}{5}} = \frac{25}{32}$$

$$I_{y} = \int_{-1}^{2}\int_{y^2}^{y + 2} x^2 \left(3x\right)\;dx\;dy = 110.7$$

$$R_{y} = \sqrt{\frac{110.7}{\frac{108}{5}}} \approx 2.26$$

Does this look correct?

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Last edited: Apr 13, 2005
2. Apr 13, 2005

### HallsofIvy

Staff Emeritus
I get what you do for M but 153/8 rather than 135/8 forMx. I get completely different answer for the others- but I may have tried to do them too fast.

3. Apr 13, 2005

### dextercioby

I dunno what Halls did,but all your calculations are perfect.I double checked them with Maple...

Daniel.

Last edited: Apr 13, 2005