- #1

- 5

- 0

Here is the problem that I'm faced with:

I understand how to do (A). Using the equation for location of center of mass,

Now I'm trying to do (B) and realize that I don't even know how to approach it at all. When the man pulls on the rope, does that mean that the woman will also move? I don't know how to take this into account to solve the problem.

I appreciate any help.

**A 52 kg woman and a 80 kg man stand 12.0 m apart on frictionless ice.**

(a) How far from the man is their center of mass (CM)?

(b) If they hold onto the two ends of a rope, and the man pulls on the rope so that he moves 2.8 m, then how far from the woman will he be?

(c) How far will the man have moved when he collides with the woman?

(a) How far from the man is their center of mass (CM)?

(b) If they hold onto the two ends of a rope, and the man pulls on the rope so that he moves 2.8 m, then how far from the woman will he be?

(c) How far will the man have moved when he collides with the woman?

I understand how to do (A). Using the equation for location of center of mass,

**[tex] x_{cm} = \frac{1}{M} \sum_{i=1}^n m_i x_i[/tex]**, I found that the man is 4.73 m from the CM.Now I'm trying to do (B) and realize that I don't even know how to approach it at all. When the man pulls on the rope, does that mean that the woman will also move? I don't know how to take this into account to solve the problem.

I appreciate any help.

Last edited: