# Center of Mass Problem

1. Nov 14, 2006

### itsme24

Hi there,

I have a question about what I'm doing wrong with the following problem:

A 45.0-kg woman stands up in a 60.0-kg canoe of length 5.00 m. She walks from a point 1.00 m from one end to a point 1.00 m from the other end. If you ignore resistance to motion of the canoe in the water, how far does the canoe move during this process?

What I did was found the x coordinate of the center of mass by doing the following math:

m_w= 45.0kg, x_w1 = 1m
m_c= 60.0kg, x_c1= 0m

x_cm = [(45.0kg*1m) + 0] / (45.0kg + 60.0kg)
x_cm = 0.429m

Then I used the same x-coordinate of the center of mass and used the second coordinate for the woman to find the second coordinate of the canoe:

x_w2 = 4m

0.429m = [(45.0kg*4m) + (60.0kg*x_c2)] / (45.0kg + 60.0kg)
x_c2 = -2.25m

Now that seems right since the ratio between the masses is 45/60 and the distance the woman traveled was 3m so 3m*0.75 = 2.25, but the answer listed is 1.29m... I would like to know if someone can see anything that I'm missing or have done wrong, it is really frustrating me. :(

2. Nov 14, 2006

Your center of mass calculation seems to be wrong, since the canoe is not included.

3. Nov 14, 2006

### itsme24

Well I included the mass of the canoe when I divided. I have the initial position of the canoe equal to 0 is there a different number I should use for that?

4. Nov 14, 2006