[SOLVED] Center of Mass problem 1. The problem statement, all variables and given/known data A 3.12 kg particle has the xy coordinates (-1.76 m, 0.652 m), and a 2.89 kg particle has the xy coordinates (0.380 m, -0.636 m). Both lie on a horizontal plane. At what (a)x and (b)y coordinates must you place a 3.74 kg particle such that the center of mass of the three-particle system has the coordinates (-0.565 m, -0.601 m)? 2. Relevant equations 3. The attempt at a solution I know this problem is extremely easy but I'm just having trouble getting it. I solve for x(com) and y(com) = -.565 = (3.12(-1.76)+2.89(.380)+3.74(x))/3.12+2.89+3.74 -.601 = (3.12(.652)+2.89(-.636)+3.74(y))/3.12+2.89+3.74 This is correct right? So how do I pull out to solve for x and y?