Center of mass question

  • Thread starter oceans93
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  • #1
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We have four squares that make up one big square. Square A is located at the top right corner, square B at the top left corner, square C at the bottom left corner, and square D at the bottom right corner. All these squares have equal masses, and the length of each square is 80 cm. What is the center of mass of the figure if square D is removed and placed on top of square B?
My solution is xcm= ((m1x1)+(m2x2)+(m3x3))/(m1+m2+m3)
m(-40+40+(2*-40))/4m
=-80/4=-20cm

ycm= m(40-40+(2*40))/4m
=80/4=20cm

Is this correct? Thank u
 

Answers and Replies

  • #2
tiny-tim
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welcome to pf!

hi oceans93! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)
My solution is xcm= ((m1x1)+(m2x2)+(m3x3))/(m1+m2+m3)
m(-40+40+(2*-40))/4m
=-80/4=-20cm

ycm= m(40-40+(2*40))/4m
=80/4=20cm

Is this correct? Thank u

looks good! :biggrin:
 
  • #3
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Even i guess its right
 

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