1. The problem statement, all variables and given/known data A club-axe consists of a symmetrical 23.0 kg stone attached to the end of a uniform 2.8 kg stick. The length of the handle is L1=91.0m and the length of the stone is L2=13.0cm. How far is the center of mass from the handle end of the club? 2. Relevant equations Center of mass equation: COM=x1m1+x2m2/(m1+m2) 3. The attempt at a solution so for my attempt i kept the lengths in cm, and my equation looks like this COM=(91.0x2.8)+(104x23.0)/(2.8+23.0). The answer im getting is 101.59 cm, which is wrong. The correct answer is 91.9cm. Any help??