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Find the x and y coordinates of the center of mass of a flat triangular plate of a height H =17.3cm and a base B = 10 Cm
Area = A = 1/2bh
x = 1/A ∫ x(f(x))
y = 1/A ∫ 1/2((f(x)^2)
Area = 1/2(10)(17.3) = 86.5
f(x) = 17.3-1.73x or 17.3-173/100x
... this represents the equation for the line of the hypt. of the triangle, with its y intercept at 17.3 and its x intercept at 10, and a slope of 17.3/10
All interals from 0 to 10
x = 1/86.5 ∫x(17.3-1.73x) = 3.333333cm
y = 1/86.5 ∫1/2((17.3-1.73x)^2) = 5.7666667cm
I've done this problems like these tons of time in calc and on my homework for physics, using this same method... but according to the answers in the book I'm getting this question wrong
their answer says the x,y coordinates are (6.67cm, 11.5cm)
I'm not really sure what I'm doing wrong
Please point out any mistakes I may have made
and the right direction I should be heading in
Thank you !
Homework Equations
Area = A = 1/2bh
x = 1/A ∫ x(f(x))
y = 1/A ∫ 1/2((f(x)^2)
The Attempt at a Solution
Area = 1/2(10)(17.3) = 86.5
f(x) = 17.3-1.73x or 17.3-173/100x
... this represents the equation for the line of the hypt. of the triangle, with its y intercept at 17.3 and its x intercept at 10, and a slope of 17.3/10
All interals from 0 to 10
x = 1/86.5 ∫x(17.3-1.73x) = 3.333333cm
y = 1/86.5 ∫1/2((17.3-1.73x)^2) = 5.7666667cm
I've done this problems like these tons of time in calc and on my homework for physics, using this same method... but according to the answers in the book I'm getting this question wrong
their answer says the x,y coordinates are (6.67cm, 11.5cm)
I'm not really sure what I'm doing wrong
Please point out any mistakes I may have made
and the right direction I should be heading in
Thank you !