A big olive (m = 0.11 kg) lies at the origin of an xy coordinate system, and a big Brazil nut (M = 0.82 kg) lies at the point (0.99, 2.1) m. At t = 0, a force F(adsbygoogle = window.adsbygoogle || []).push({}); o= (4i+ 4j) N begins to act on the olive, and a force Fn= (-4i-3j) N begins to act on the nut. What is the(a)x and(b)y displacement of the center of mass of the olive-nut system at t = 4.6 s, with respect to its position at t = 0?

I first started approaching the problem by doingE(sigma)mixi/Emi, and the same for the y-direction. So, for x-direction, it would be:

(.99molive+ 0mnut)/(.82kg + .11kg)

for the y-direction, it would be:

(2.1molive+ 0mnut)/(.82kg + .11kg)

I don't even know if I did those correctly.

For the rest, they give you the force in both directions and the duration time (4.6 sec). I have to find the displaceent, which means I first have to find the center of mass for 0 seconds and then for 4.6 seconds.

Can someone help me with how to approach this problem? Thank you.

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# Homework Help: Center of mass (vectors)

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