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1. Homework Statement
figure attached:
Uniform beam with mass M,is placed horizontally,pivoted about it's center
on the beam there are two small masses m1 and m2,connected by a spring,the system is in equilibrium,and at t=0 the spring is cut,and m1 and m2 slide on the beam.(their speed is not given),there is friction between the beam and the masses.
given: m2>m1
the problem is to find the direction to which the beam will tilt
3. The Attempt at a Solution
I thought that I should look at the speed of the center of mass.
motion of m1:
V1 = V'1  m1g*Y*t (v'1 is the speed upon release(I assumed) Y is coefficient of friction)
same for m2 so Vcm is:
[V1*m1 + V2*m2] / (M+m1+m2)
I cannot get anything out of this.
thanks for the help.
figure attached:
Uniform beam with mass M,is placed horizontally,pivoted about it's center
on the beam there are two small masses m1 and m2,connected by a spring,the system is in equilibrium,and at t=0 the spring is cut,and m1 and m2 slide on the beam.(their speed is not given),there is friction between the beam and the masses.
given: m2>m1
the problem is to find the direction to which the beam will tilt
3. The Attempt at a Solution
I thought that I should look at the speed of the center of mass.
motion of m1:
V1 = V'1  m1g*Y*t (v'1 is the speed upon release(I assumed) Y is coefficient of friction)
same for m2 so Vcm is:
[V1*m1 + V2*m2] / (M+m1+m2)
I cannot get anything out of this.
thanks for the help.
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