- #1

cmrgator

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- Thread starter cmrgator
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- #1

cmrgator

- #2

- 136

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Cut the circle out of the remaing 3 quarters of the large square, now you have a symmetrical shape about both x and y axis. The center of mass is the center, so we can now ignore this part.

Now what is the center of mass of the 3 circles?

- #3

- 35

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Anyway, even with the corner piece, I wouldn't know what to do.

- #4

- 136

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Oops, I missed the part about the corner cut out...

I guess its back to x_bar y_bar in the first place then....

Well, it could still be done the way I was suggesting, don't know if its any easier though....but the point was to take out all area symmetrical about both axis, to simplify the problem.

I guess its back to x_bar y_bar in the first place then....

Well, it could still be done the way I was suggesting, don't know if its any easier though....but the point was to take out all area symmetrical about both axis, to simplify the problem.

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