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Homework Help: Central Maximum

  1. Apr 4, 2005 #1
    A diffraction pattern is produced on a screen 140 cm from a single slit using monochromatic light of wavelength 500 nm. The distance from the center of the central maximum to the first order maximum is 3 mm. Calculate the slit width (assume first order maximum is halfway between the first and second order minima).

    So things we know-
    From the slit to the screen is 140 cm
    Wavelength = 500 nm
    from the center of the central maximum to the first order is 3 mm.

    if we use: Sin of the angle = (M * Wavelength)/d =
    sin of the angle = (1 * 500x10^-7) / .003

    That gives the angle of the central maximum which we can then plug into
    sin angle=wavelength/slit width?
     
  2. jcsd
  3. Apr 4, 2005 #2
    Does this look right or did i go wrong somewhere? Any help is appreciated greatly
     
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