A diffraction pattern is produced on a screen 140 cm from a single slit using monochromatic light of wavelength 500 nm. The distance from the center of the central maximum to the first order maximum is 3 mm. Calculate the slit width (assume first order maximum is halfway between the first and second order minima).(adsbygoogle = window.adsbygoogle || []).push({});

So things we know-

From the slit to the screen is 140 cm

Wavelength = 500 nm

from the center of the central maximum to the first order is 3 mm.

if we use: Sin of the angle = (M * Wavelength)/d =

sin of the angle = (1 * 500x10^-7) / .003

That gives the angle of the central maximum which we can then plug into

sin angle=wavelength/slit width?

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# Homework Help: Central Maximum

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