1. The problem statement, all variables and given/known data a thin uniform wire is bent to form two equal sides AB and AC of triangle ABC , where AB=AC=5cm . the third side BC , of length 6cm is made from uniform wire of twice the density of the first . the distance of centre of mass from A is ? 2. Relevant equations x centre of mass = m1R1+m2r2/ sum of masses(where r= centre of mass of particle in sys.) λ=m/l ( where m= mass of object , l=length ) uniform density formula 3. The attempt at a solution i was able to calculate the X c.o.m which is = 12λ*lenght of rod BC/2 but was unable to calculate its y coordinate ?