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Centrifugal force

  1. Apr 22, 2009 #1
    http://users.on.net/~rohanlal/cent.jpg [Broken]

    my attempt:
    The car becomes lighter as it passes over the arc therefore its going to exert a force on the road that is less than its normal force.
    f=mv^2/r
    f=1710(16.6)^2/38.5 = 12239.15844
    9.8 x 1710 = 16758
    16758-12239.15844
    this is incorrect, what am i doing wrong?
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Apr 22, 2009 #2

    Delphi51

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    Looks okay to me. I got 4536 N using g = 9.81.
     
  4. Apr 22, 2009 #3
    As a matter of fact let me do the math for ya here.(I've no idea if my expression is clear or not cuz English is not my mother tongue.)
    The gravity exerted on the car is :
    G=mg=16758N
    And the Centripetal force needed is:
    f=mv^2/R=12239.15844N
    As the forces exerted on the car is the Centripetal force if we take the ground as the reference frame
    so
    N+f=G
    N=4518.84156N
    This is right the force the road exert on the car...if I'm asked to solve it.
    I don't see any problems unless it's a problem of relativity or Quantunm Mechanics...
     
  5. Apr 23, 2009 #4
    it says to use 9.8 for gravity and round off to the nearest tenth. What would it be then?
     
  6. Apr 23, 2009 #5
    Simply 9.8? :tongue2:
     
  7. Apr 26, 2009 #6
    That's exactly what I did.
    I don't see anything wrong.
     
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