10 lbs. steel wheel with its center of gravity at 6 inches from the axle rotating within a circular frame at 7200 rpm
10lbs. x 6 inches x 72002rpms x 0.000028416(constant) = 88,385 lbs.
The Attempt at a Solution
10 x 6 x 72002 x 0.000028416 = 88,385 lbs.
The question is "Are my calculations correct and does that mean that the force against the perimeter frame from the steel wheel is actually 88,385 lbs.? If not what is the actual force?