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I can't seem to get the right answer...

R = 1.50 x 10^11

and I figure that 1 day/rev = 86400 sec/rev

So: [tex]\frac {2 \pi 1.50 * 10^{11}}{86400}[/tex] is the velocity, and then plug that into [tex]\frac {v^2}{r}[/tex] but I keep on getting 700 something..what am I doing wrong?

Question 2: At what minimum speed must a roller coaster be traveling when upside down at the top of a circle if the passengers are not to fall out? R = 8.6m

What I think you have to do is

[tex] mg + F_c = m * \frac {v^2}{R}[/tex]

but I don't know what F would be...or am I approaching this the wrong way?

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# Homework Help: Centripetal acceleration of Earth around Sun?

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