A box rests at a point 2.0m from the axis of a horizontal circular platform. The coefficient of static frictin between box and platform is 0.25. As the rate of rotation of the platform is slowly increased from zero, at what frequency will the box first slide?
The Attempt at a Solution
a.centripetal = mu(g)
=0.25(g) = 2.45m/s^2
frequency=sqrt(a.centripetal*r)/2*pi*r = 0.176 rev/s
Have i done this correctly?