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Centripetal acceleration

  1. Nov 9, 2007 #1
    1. The problem statement, all variables and given/known data
    A box rests at a point 2.0m from the axis of a horizontal circular platform. The coefficient of static frictin between box and platform is 0.25. As the rate of rotation of the platform is slowly increased from zero, at what frequency will the box first slide?

    2. Relevant equations

    3. The attempt at a solution

    a.centripetal = mu(g)

    =0.25(g) = 2.45m/s^2


    frequency=sqrt(a.centripetal*r)/2*pi*r = 0.176 rev/s

    Have i done this correctly?
  2. jcsd
  3. Nov 9, 2007 #2
    I arrived at the same answer, but you'll probably want to use two sig figs because the coefficient of static friction and radius have two sig figs.
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