Centripetal acceleration

  • Thread starter tascja
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  • #1
tascja
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Homework Statement


Calculate the magnitude of the centripetal acceleration at 8.4 cm from the centre of the centrifuge when it is spinning at 6.0x10^4 rpm. Express your answer in terms of g (acceleration due to Earth's gravity.)


Homework Equations


Ac = v^2 /
r

The Attempt at a Solution


I know the solution i just don't understand what they are asking from me when they say:
Express your answer in terms of g (acceleration due to Earth's gravity
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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I know the solution i just don't understand what they are asking from me when they say:
Express your answer in terms of g (acceleration due to Earth's gravity


For example if you got your answer as 19.62ms^-2 that would be the same as 2*9.81 and since 9.81 is g, the acceleration would be 2g.

So what you want to do is divide your answer by 'g' i.e. 9.81, and the resulting number would be in terms of g.
 
  • #3
tascja
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thank you! so if my answer was 1.5x10^14 m/s^2 it would then become 1.53x10^13g ?
 
  • #4
rock.freak667
Homework Helper
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That would be it depending on what value you use for 'g'
 
  • #5
Gokul43201
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thank you! so if my answer was 1.5x10^14 m/s^2 it would then become 1.53x10^13g ?
Yes, but that number is not the correct value of the acceleration.
 
  • #6
tascja
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Oh! its not velocity that's given its frequency
 
  • #7
tascja
87
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so the actual answer would be
Ac = 4.3x10^13 m/s^2

and in terms of g
= 4.3x10^12g
 

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