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Centripetal acceleration

  1. Apr 18, 2008 #1
    1. The problem statement, all variables and given/known data
    Calculate the magnitude of the centripetal acceleration at 8.4 cm from the centre of the centrifuge when it is spinning at 6.0x10^4 rpm. Express your answer in terms of g (acceleration due to Earth's gravity.)


    2. Relevant equations
    Ac = v^2 /
    r

    3. The attempt at a solution
    I know the solution i just dont understand what they are asking from me when they say:
    Express your answer in terms of g (acceleration due to Earth's gravity
     
  2. jcsd
  3. Apr 18, 2008 #2

    rock.freak667

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    Homework Helper



    For example if you got your answer as 19.62ms^-2 that would be the same as 2*9.81 and since 9.81 is g, the acceleration would be 2g.

    So what you want to do is divide your answer by 'g' i.e. 9.81, and the resulting number would be in terms of g.
     
  4. Apr 18, 2008 #3
    thank you! so if my answer was 1.5x10^14 m/s^2 it would then become 1.53x10^13g ?
     
  5. Apr 18, 2008 #4

    rock.freak667

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    That would be it depending on what value you use for 'g'
     
  6. Apr 18, 2008 #5

    Gokul43201

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    Gold Member

    Yes, but that number is not the correct value of the acceleration.
     
  7. Apr 18, 2008 #6
    Oh! its not velocity that's given its frequency
     
  8. Apr 18, 2008 #7
    so the actual answer would be
    Ac = 4.3x10^13 m/s^2

    and in terms of g
    = 4.3x10^12g
     
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