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Centripetal acceleration

  1. Feb 1, 2012 #1
    1. The problem statement, all variables and given/known data

    A short track speed skaer is making a turn at one end an ice rink, increasing his speed frm uniformly 10 m/s t 20 m/s in two seconds. The radius of the turn is 5 meters. While he is in the middle of the turn, and mving at 15 m/s, what is

    a. tangential acceleration
    b. centripetal acceleration
    c. magnitude of his acceleration

    2. Relevant equations
    v^2/r
    magnitude of a = sqrt((tangential)^2+(centripetal)^2)

    3. The attempt at a solution

    tangential= 15 m/s
    centripetal=(15m/s)^2/(5m)=45m/s^2
    magnitude of acceleration = sqrt((15)^2+(45)^2)=47.43

    Please help me out here.
     
  2. jcsd
  3. Feb 1, 2012 #2

    SammyS

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    Hello Dylan6866. Welcome to PF.

    If you mean that the tangential acceleration = 15m/s, I'm afraid that's wrong. Wrong units and wrong number.

    The centripetal acceleration is correct.
     
  4. Feb 1, 2012 #3
    Thank you. I figured it out.
     
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